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Do you have any queries regarding Ozeki NG - SMS Gateway software? If so, leave your comments below. I'm sure this will help you. Ozeki NG - SMS Gateway ( ) We use cookies to improve our website and your experience when using it. Cookies used for the essential operation of the site have already been set. To find out more about the cookies we use and how to delete them, see our privacy policy. By using our website you consent to our use of cookies. By using our website you consent to our use of cookies. Privacy policyQ: How to find all the ways to create a number of leafs with certain weight distribution I have a question that looks like this: "Say you have a set of $n$ leaves, how many ways can you arrange them in order so that the weight of the leftmost leaf is $x_1$; the weight of the second from left is $x_2$; and so on until the weight of the leftmost leaf is $x_k$. I am not sure what to call this, so I will try to give a small example. Let $n = 3$. Then there are $3! = 6$ ways to arrange the leafs, but I am not sure how to show this. More examples: Let $n = 3$ and $x_1 = 5$, $x_2 = 2$, $x_3 = 7$. Then there are $6$ ways to do this. Let $n = 3$ and $x_1 = 4$, $x_2 = 1$, $x_3 = 9$. Then there are $6$ ways to do this. Let $n = 3$ and $x_1 = 6$, $x_2 = 3$, $x_3 = 5$. Then there are $5$ ways to do this. I thought that this problem must have a known name, but I couldn't find any. Any suggestions? Thanks a lot! A: For any given $n$ and $k$, I claim that there are $f_{n,k}$ ways of arranging $n$ leaves so that the leftmost leaf receives weight $k$, the second from left receives weight $k-1

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